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10x^2+88x-110=0
a = 10; b = 88; c = -110;
Δ = b2-4ac
Δ = 882-4·10·(-110)
Δ = 12144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12144}=\sqrt{16*759}=\sqrt{16}*\sqrt{759}=4\sqrt{759}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-4\sqrt{759}}{2*10}=\frac{-88-4\sqrt{759}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+4\sqrt{759}}{2*10}=\frac{-88+4\sqrt{759}}{20} $
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